Friday, October 5, 2007
Are You as Smart as a Third Year University Student? Q4
Question 1
Question 2
Question 3The open-chain form of fructose 1,6-bisphosphate is shown as the substrate for the aldolase reaction. Why?
a) the open-chain form is more abundant inside the cell
b) cyclic molecules destabilize the transition state
c) the product of the previous reaction in glycolysis
is the open-chain form
d) the open-chain form is thermodynamically more stable
and this contributes to the positive standard Gibbs free
change for the reaction
e) the active site of the enzyme can’t accommodate the
furanose or pyranose forms
Labels:
Biochemistry
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